250n^2-490=0

Solution for 250n^2-490=0 equation:

250n^2-490=0

a = 250; b = 0; c = -490;
Δ = b2-4ac
Δ = 02-4·250·(-490)
Δ = 490000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{490000}=700$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-700}{2*250}=\frac{-700}{500}
=-1+2/5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+700}{2*250}=\frac{700}{500}
=1+2/5
$